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16x^2-68x+60=0
a = 16; b = -68; c = +60;
Δ = b2-4ac
Δ = -682-4·16·60
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-28}{2*16}=\frac{40}{32} =1+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+28}{2*16}=\frac{96}{32} =3 $
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